Answer: B (100-20) i.e 80% of MP = (100+60) i.e 160% of CP Percentage of CP = 100-25 = 75% Hence profit % = {160/80 * 75%of CP } - 100% = 50%
Q. No. 14:
A man buys 200kg of dal at Rs 7.25 per kg and 400kg at Rs 5.75 per kg. He mixes and sells one-third of the mixture at Rs 6 per kg. At what price per kilogram should he sell the remaining mixture so that he may earn a profit of 20% on the whole?
Answer: C 7.25 * 200 = 1450 5.75 * 400 = 2300 CP = 3750 => SP = 4500 1/3 rd of 600 = 200 at the rate of 6 = 1200 => 400 kg at Rs 3300 => SP = 3300/400 = Rs 8.25/kg
Q. No. 15:
If a person makes a toys, which grows at a simple rate of 10% in a decade and compounds from decade to decade. Find the number of toys at the beginning of the 1980s if the toys at the beginning of the 2000s is 363000 toys.
Answer: D Compounded growth rate per decade = 10% Let P be the toys in 1980s => 3,63,000 = P((100+10)/100)2 => 1.21P = 3,63,000 => P= 3,00,000
Q. No. 16:
Vineet calculate his profit percentage on the selling price whereas Roshan calculates his profit on the cost price. They find that the difference of their profits is Rs 275. If the selling price of both of them are the same and Vineet gets 25% profit and Roshan gets 15% profit, then find their selling price.
Answer: B Let the SP of Vineet and Roshan be x. 15% profit on CP = 15/115 * 100 = 300/23 % profit on SP. => (x-25)/100 - 300x/(23*100) = 275 => x = Rs 2300.
Q. No. 17:
A farmer sold a cow and an Ox for Rs 800 and got a profit of 20% on the cow and 25% on the ox. If he sells the cow and the ox for Rs 820 and gets a profit of 25% on the cow and 20% on the ox, the individual cost price of the cow and the ox is :
Answer: C Let CP of cow be x and CP of ox be y. x* 120/100 + y* 125/100 = 800...........(i) x* 125/100 + y* 120/100 = 820...........(ii) On solving both the equations, we get x = 530.6 and y = 131.14.